The 13th Blue Bridge Cup Software Competition Provincial Competition (C/C++ University Group C)

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  Persimmons should be picked softly, and where they are written.

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Question A: Arrange Letters

Total score for this question: $5$ points

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【Problem Description】

  Little Blue wants to arrange the letters in a string according to their order in the alphabet.

  For example, $LANQIAO$ is$AAILNOQ。$ _

  又如，$GOODGOODSTUDYDAYDAYUP$ is$AADDDDDGGOOOOPSTUUYY。\_$ _

  For the following strings, what is the string after permutation?

  $WHERETHEREISAWILLTHEREISAWAY$

【Answer submission】

  This is a fill-in-the-blank question, you only need to calculate the result and submit it. The result of this question is a string consisting of uppercase letters. Only fill in this string when submitting the answer. Fill in the extra content will not be able to score.

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AAAEEEEEEHHHIIILLRRRSSTTWWWY

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#include <stdio.h>

char *str = "WHERETHEREISAWILLTHEREISAWAY";

int total[128];

int main() {
    
    
    while (*str) ++total[*str++];
    for (char i = 'A'; i <= 'Z'; ++i)
        while (total[i]--) putchar(i);
}

  The pointer flies around and it's over.

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Question B: Special Hours

Total score for this question: $5$ points

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【Problem Description】

  $2022$ years$Feb$ 22$22$ days$22$:$20$ is a meaningful time, the year is$2022$ by$3$ 2$2$ and$1$ 0$0$ , if the month and day are written as$4$ digits, for$0222$ , also by$3$ 2$2$ and$1$ 0$0$ , if the hour and minute in the time are written as$4$ bits, or by$3$ 2$2$ and$1$ 0$0$ composition.

  Xiaolan is very interested in such times, he also found other similar examples, such as $111$ Year$10$ 11$11$ day$01$:$11$，$2202$ 2$Feb$ 22$22$ days$22$:$02$ and so on.

  Excuse me, how many times are there in this year written as $4$ digits, month and day written as$4$ bits, time is written as$4$ digits after 3 by$3$ one-of-a-kind numbers and$1$ composed of another number. Attention$1111$ Year$1$ November$11$$11$ day$11$:$11$ doesn't count because it doesn't have two numbers in it.

【Answer submission】

  This is a fill-in-the-blank question, you only need to calculate the result and submit it. The result of this question is an integer. Only fill in this integer when submitting the answer. Fill in the extra content will not be able to score.

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212

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  in 3 3Insert 1 1$into\; 3$ identical single digits$1\; single$ digit, obviously can form$4$ different numbers (not necessarily$4$ digits), so we can have another valid month, day, hour and minute with$4$ different years form a mapping relationship, as long as the legal number of days, months, hours and minutes is counted, multiply it by a$4$ , the answer is calculated.

#include <stdio.h>

int buff[10], ans = 0;

int days[]{
    
    0, 31, 29, 31, 30 ,31, 30, 31, 31, 30 ,31, 30, 31};

int main() {
    
    
    for (int MM = 1; MM <= 12; ++MM)
        for (int dd = 1; dd <= days[MM]; ++dd)
            for (int HH = 0; HH < 24; ++HH)
                for (int mm = 0; mm < 60; ++mm) {
    
    
                    for (int i = 0; i < 10; ++i) buff[i] = 0;
                    ++buff[MM / 10]; ++buff[MM % 10];
                    ++buff[dd / 10]; ++buff[dd % 10];
                    bool flag1 = 1, flag2 = 1;
                    for (int i = 0; i < 10; ++i)
                        if (buff[i] == 3) flag1 = 0;
                        else if (buff[i] == 1) flag2 = 0;
                    if (flag1 || flag2) continue;
                    --buff[HH / 10]; --buff[HH % 10];
                    --buff[mm / 10]; --buff[mm % 10];
                    for (int i = 0; i < 10; ++i)
                        if (buff[i] != 0) flag1 = 1;
                    if (!flag1) ++ans;
                }
    printf("%d", ans << 2);
}

Let's write group A first