package com.zhangsan.controller;
import org.apache.commons.lang.StringUtils;
public class Test {
// 1、开头不能是数字
// 2、包含大写、小写字母、数字
// 3、至少一个特殊字符
public static boolean testString(String s){
String begin = s.substring(0,1);
// 1、开头不能是数字
boolean numeric = StringUtils.isNumeric(begin);
if (numeric){
return false;
}
// 2、包含大写、小写字母、数字
char[] charArray = s.toCharArray();
int specialCount = 0, lowerCount = 0, upperCount = 0, numberCount = 0;
for (char c : charArray) {
int ascValue = c;
// System.out.println(ascValue);
if((ascValue > 32 && ascValue < 48) || ascValue == 64){
specialCount++;
} else if (ascValue > 47 && ascValue < 58) {
numberCount++;
}else if (ascValue > 64 && ascValue < 91) {
upperCount++;
}else if (ascValue > 96 && ascValue < 123) {
lowerCount++;
}
}
return specialCount >= 1 && lowerCount >= 1 && upperCount >= 1 && numberCount >= 1;
}
public static void main(String[] args) {
String s1 = "1@zhangsan"; // false
String s2 = "Zhangsan@1"; // true
System.out.println(testString(s1));
}
}
The interviewer asked me to verify whether the user name is legal, so I directly took out the most basic and cumbersome code
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Origin blog.csdn.net/weixin_44019553/article/details/131643473
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