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foreword
This article introduces two methods of drawing a rhombus in C language. Of course, the two methods have advantages and disadvantages, and which one you prefer is entirely up to you. Of course, I prefer method two.
1. Method 1
General approach based on double for loops.
The key lies in the characterization of several triangles.
#include <stdio.h>
int main()
{
int n;
scanf("%d", &n);
for (int i = 0; i <= n / 2; ++i)
{
for (int j = n / 2 - i; j > 0; --j)
{
printf(" ");
}
for (int k = 0; k < 2 * i + 1; ++k)
{
printf("*");
}
printf("\n");
}
for (int i = 1; i <= n - n / 2 ; ++i)
{
for (int j = 1; j <= i; ++j)
{
printf(" ");
}
for (int k = n - 2 * i; k > 0; --k)
{
printf("*");
}
printf("\n");
}
return 0;
}
2. Method 2
Based on simple mathematics - the simplest form of linear programming.
We only need to choose the appropriate coordinate origin (very important, can simplify the calculation), and then calculate the expression corresponding to each side of the rhombus.
x + y <= n / 2
-x + y <= n / 2
-x - y <= n / 2
x - y <= n / 2
put together is
|x| + |y| <= n/2
#include <stdio.h>
#include <math.h>
int main()
{
int n = 0;
scanf("%d", &n);
for (int i = -n / 2; i <= n / 2;++i)
{
for (int j = n / 2; j >= -n / 2; --j)
{
if (fabs((double)i) + fabs((double)j) <= n / 2)
printf("*");
else
printf(" ");
}
printf("\n");
}
return 0;
}
Notice
For the second method, if you want to draw a hollow diamond, you only need to change the judgment condition to fabs((double)i) + fabs((double)j) == n / 2, isn’t it very convenient. But for method one, you have to use your brains again. As for how to write it specifically, I won't write too much here.
Summarize
That's all there is to it. Of course, both approaches have their advantages and disadvantages. No matter which method you like, don't be stingy with your praise!