topic:
Input the following pattern on the screen in C language:
=========================================================================
Ideas:
general idea:
(one).
Enter the number of rows in the upper half of the rhombus -- scanf() function
(two).
Use a for loop to print the triangle ,
The number of triangle lines in the upper half of the rhombus -- i < line
(Note: It is only the number of rows of triangles in the upper part of the rhombus , and the upper part is a regular triangle )
Use the embedded for loop to loop and print out the space :
The upper part of the diamond-shaped space rules :
j < line - 1 - i
Such as : line is equal to 7 , then,
The first line prints 7-1-0=6 spaces ;
The second line prints 7-1-1=5 spaces .
Embed the second for loop and print the * number in the upper half of the diamond :
The rule of the rhombus * in the upper part :
j < 2 * i + 1
Such as : line is equal to 7 , then,
The first line prints 2*0+1=1 * number ;
The second line prints 2*1+1=3 * numbers .
After printing a line , wrap it :
printf("\n");
(three).
Use the for loop to print the triangle in the lower half of the rhombus ,
Number of rows of triangles in the lower half of the rhombus -- i < line-1
(Note: It is the number of rows of triangles in the lower half of the rhombus , and the lower part is an inverted triangle )
Use the embedded for loop to loop and print out the spaces in the lower half of the rhombus :
The lower half of the rhombus space rule :
j <= i
For example : line-1 is 7-1=6 , then,
print the first line
j=0，i=0，j<=i ，
1 space ;
print the second line
j=0，i=1，j<=i，
2 spaces .
Embed the second for loop and print the * number in the lower half of the diamond :
The rule of the rhombus * in the lower part :
j < 2*(line-1-i)-1
For example : line-1 is 7-1=6 , then,
The first line prints 2*(7-1-0)-1=11 * numbers ;
The second line prints 2*(7-1-1)-1=9 * numbers .
After printing a line , wrap it :
printf("\n");
first step:
Enter the number of rows in the upper half of the rhombus -- scanf() function
Implementation code:
#include <stdio.h> int main() { //输入菱形上半部分行数 -- scanf()函数: int line = 0; //上半行数 //输入： scanf("%d", &line); return 0; }Realize the picture:
Step two:
（1）.
Use a for loop to print the triangle ,
The number of triangle lines in the upper half of the rhombus -- i < line
(Note: It is only the number of rows of triangles in the upper part of the rhombus , and the upper part is a regular triangle )
（2）.
Use the embedded for loop to loop and print out the space :
The upper part of the diamond-shaped space rules :
j < line - 1 - i
Such as : line is equal to 7 , then,
The first line prints 7-1-0=6 spaces ;
The second line prints 7-1-1=5 spaces .
（3）.
Embed the second for loop and print the * number in the upper half of the diamond :
The rule of the rhombus * in the upper part :
j < 2 * i + 1
Such as : line is equal to 7 , then,
The first line prints 2*0+1=1 * number ;
The second line prints 2*1+1=3 * numbers .
（4）.
After printing a line , wrap it :
printf("\n");
Implementation code:
#include <stdio.h> int main() { //输入菱形上半部分行数 -- scanf()函数: int line = 0; //上半行数 //输入： scanf("%d", &line); //菱形上半部分的打印：行数 -- line int i = 0; for (i = 0; i < line; i++) { //打印一行，先打印空格，再打印*号 //内嵌for循环 打印空格： //上半部分空格规律： // line-1-i：假设行数是7， //第一行打印7-1-0=6个空格；第二行打印7-1-1=5个空格…… int j = 0; for (j = 0; j < line-1-i; j++) { printf(" "); //打印空格 } //内嵌第二个for循环 打印*号： //上半部分*号规律： // 2*i+1：假设行数是7， //第一行打印2*0+1个*号；第二行打印2*1+1个*号…… for (j = 0; j < 2*i+1; j++) { printf("*"); //打印*号 } //打印完一行后就进行换行： printf("\n"); } return 0; }Realize the picture:
third step:
（1）.
Use the for loop to print the triangle in the lower half of the rhombus ,
Number of rows of triangles in the lower half of the rhombus -- i < line-1
(Note: It is the number of rows of triangles in the lower half of the rhombus , and the lower part is an inverted triangle )
（2）.
Use the embedded for loop to loop and print out the spaces in the lower half of the rhombus :
The lower half of the rhombus space rule :
j <= i
For example : line-1 is 7-1=6 , then,
print the first line
j=0，i=0，j<=i ，
1 space ;
print the second line
j=0，i=1，j<=i，
2 spaces .
（3）.
Embed the second for loop and print the * number in the lower half of the diamond :
The rule of the rhombus * in the lower part :
j < 2*(line-1-i)-1
For example : line-1 is 7-1=6 , then,
The first line prints 2*(7-1-0)-1=11 * numbers ;
The second line prints 2*(7-1-1)-1=9 * numbers .
（4）.
After printing a line , wrap it :
printf("\n");
Implementation code:
#include <stdio.h> int main() { //输入菱形上半部分行数 -- scanf()函数: int line = 0; //上半行数 //输入： scanf("%d", &line); //菱形上半部分的打印：行数 -- line int i = 0; for (i = 0; i < line; i++) { //打印一行，先打印空格，再打印*号 //内嵌for循环 打印空格： //上半部分空格规律： // line-1-i：假设行数是7， //第一行打印7-1-0=6个空格；第二行打印7-1-1=5个空格…… int j = 0; for (j = 0; j < line-1-i; j++) { printf(" "); //打印空格 } //内嵌第二个for循环 打印*号： //上半部分*号规律： // 2*i+1：假设行数是7， //第一行打印2*0+1个*号；第二行打印2*1+1个*号…… for (j = 0; j < 2*i+1; j++) { printf("*"); //打印*号 } //打印完一行后就进行换行： printf("\n"); } //菱形下半部分的打印：行数 -- line-1 for (i = 0; i < line-1; i++) { //打印一行，先打印空格，再打印*号 //内嵌for循环 打印空格： //下半部分空格规律： // j<=i：假设行数是7-1=6， //第一行打印j=0,i=0,j<=i,1个空格；第二行打印j=0,i=1,j<=i,2个空格…… int j = 0; for (j = 0; j <= i; j++) { printf(" "); //打印空格 } //内嵌第二个for循环 打印*号： //下半部分*号规律： // 2*(line-1-i)-1：假设行数是7-1=6， //第一行打印2*(7-1-0)-1,11个*号；第二行打印2*(7-1-1)-1,9个*号…… for (j = 0; j < 2*(line-1-i)-1; j++) { printf("*"); //打印*号 } //打印完一行后就进行换行： printf("\n"); } return 0; }Realize the picture:
Final code and implementation effect
Final code:
#include <stdio.h> int main() { //输入菱形上半部分行数 -- scanf()函数: int line = 0; //上半行数 //输入： scanf("%d", &line); //菱形上半部分的打印：行数 -- line int i = 0; for (i = 0; i < line; i++) { //打印一行，先打印空格，再打印*号 //内嵌for循环 打印空格： //上半部分空格规律： // line-1-i：假设行数是7， //第一行打印7-1-0=6个空格；第二行打印7-1-1=5个空格…… int j = 0; for (j = 0; j < line-1-i; j++) { printf(" "); //打印空格 } //内嵌第二个for循环 打印*号： //上半部分*号规律： // 2*i+1：假设行数是7， //第一行打印2*0+1个*号；第二行打印2*1+1个*号…… for (j = 0; j < 2*i+1; j++) { printf("*"); //打印*号 } //打印完一行后就进行换行： printf("\n"); } //菱形下半部分的打印：行数 -- line-1 for (i = 0; i < line-1; i++) { //打印一行，先打印空格，再打印*号 //内嵌for循环 打印空格： //下半部分空格规律： // j<=i：假设行数是7-1=6， //第一行打印j=0,i=0,j<=i,1个空格；第二行打印j=0,i=1,j<=i,2个空格…… int j = 0; for (j = 0; j <= i; j++) { printf(" "); //打印空格 } //内嵌第二个for循环 打印*号： //下半部分*号规律： // 2*(line-1-i)-1：假设行数是7-1=6， //第一行打印2*(7-1-0)-1,11个*号；第二行打印2*(7-1-1)-1,9个*号…… for (j = 0; j < 2*(line-1-i)-1; j++) { printf("*"); //打印*号 } //打印完一行后就进行换行： printf("\n"); } return 0; }Realize the effect:
