Calculate the value of 1/1-1/2+1/3-1/4+1/5 ... + 1/99 - 1/100
I haven't been on CSDN for several days in the middle, and I am still learning. Today, I am full of blood and resurrected. Let's write a few small practice codes, learn C/C++ again, and start attacking the master's thesis at the same time. mutual encouragement!
The solution to this question can be divided into two parts and then summed, that is, sum=sum1+sum2;
where sum1 is used to represent odd items
and sum2 is used to represent even items
Note: because they are all fractions, so for sum, sum1 and When sum2 is defined, it should be of type float.
The code is:
#include<stdio.h>
#include<stdlib.h>
int main()
{
int i, j;
float sum = 0;
float sum1 = 0;
float sum2 = 0;
for (i = 1; i < 100; i += 2)
sum1 = sum1 + 1.0 / i;
for (j = 2; j <= 100; j +=2)
sum2 = sum2 - 1.0 / j;
sum = sum1 + sum2;
printf("%f\n", sum);
system("pause");
return 0;
}
The output is:
