#include <stdio.h>
#include <math.h>
/*
求π的近似值 π/4 = 1-1\3+1\5-1\7,要求精度在10^-6以上。
*/
int main()
{
int sign = 1;//每一项的标志,第一项为正
double pi = 0.0, term = 1.0,n=1.0;//n用来做每项的分母,term是每项的值
while (fabs(term) >= 1e-6)//科学计数法,相当于10^-6
{
pi += term;
n =n+2;
sign =-sign;
term = sign/n;
}
pi = pi*4;
printf("%10.8f\n",pi);//最少输出10位,如果不够10位,左边补0,超出10位,会扩充。小数点后最少8位。
return 0;
}
Code exercise - find π by formula method
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Origin blog.csdn.net/weixin_48060069/article/details/130046950
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