Code exercise - find π by formula method

#include <stdio.h>
#include <math.h>

/*
    求π的近似值 π/4 = 1-1\3+1\5-1\7,要求精度在10^-6以上。
*/

int main()
{
    int sign = 1;//每一项的标志,第一项为正
    double pi = 0.0, term = 1.0,n=1.0;//n用来做每项的分母,term是每项的值
   while (fabs(term) >= 1e-6)//科学计数法,相当于10^-6
   {
        pi += term;
        n =n+2;
        sign =-sign;
        term = sign/n;
   }
    pi = pi*4;
    printf("%10.8f\n",pi);//最少输出10位,如果不够10位,左边补0,超出10位,会扩充。小数点后最少8位。
    return 0;
}

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Origin blog.csdn.net/weixin_48060069/article/details/130046950