Xueeryou 2020 Senior High School Entrance Examination Special Classification Training Math answers are organized by Answer Analysis Network to get more primary school teaching aids
For answer analysis, please search on WeChat and pay attention to "Answer Analysis Network".
High school entrance examination mathematics topic classification training (1) real numbers, 1.c2.b3.c4.d5.c6.a7.c8.c9.D10.2, 11.212.313.414.-315.716.40353, 17.(1)23+3 (2)5(3)-2(4)418.(-6)÷3×(-√12)+3-15, or (6x÷3×(-√12)-3=9, etc. 19. (1) Taking B as the origin, points A and C correspond to -21=-2+0+1--1 respectively. Taking point C as the origin, p=(-1-2)+(-1)+0=-4 (2)p=(-28-1+2)+28)880.(1)-i1(2)(1+i)×(3--33i auxiliary file(3)i+i2+i2+21. (1) 30 hdzuoye.com (2) Suppose that after x seconds, the distance from point N to point is equal. At this time, the number corresponding to point M is 3x-10, and the number corresponding to point N is 2x ①If point M and point N are at point O On both sides, then 10-3x=2x, the solution is x=2; ②If the point M and the point N are coincident, then 3x-10=2x, the solution is =10, so after 2 seconds or 10 seconds, the points M and N reach the origin The distance of O is equal to 22. (1) 1+3+5+7=16=42, let the number of balls in the nth picture be Sn, observe and find the law: S1=1+3=22, S2=1 +3+5=32, S3=1+3+5+7=42,…,∴S-1=1+3+5+…+(2n-1)=n2, so the answer is 42+n2(2 ) Observe the figure and find that: the black ball in the figure can be divided into three parts: 1 to n lines, n+1 line, n+2 line to 2n+1 line, namely 1+3+5+…+(2n-1)+[ 2(n+1)-1]+(2n-1)+…+5+3+1=1+3+5+…+(2n1)+(2n+1)+(2n-1)+…+ 5+3+1=S-+(2n+1)+Sn-=n2+2n+1+n2=2n2+2n+1