1028. Census

topic here

Store the date in a string, and then judge one by one, the oldest person is younger than the maximum date (2014/09/06), and the youngest person is older than the minimum date (1814/09/06), and then put the name Save, judge, overwrite the name and date one at a time, and leave the oldest and youngest at the end.

Note: There was a point that didn't pass when I submitted, and the problem displayed was that the format was wrong. Later, I checked the case that count was 0, and found that when the output was 0, there was a space after it, so I added a judgment on whether the count is 0 or not. .

#include <iostream>
using namespace std;

intmain()
{
	int n;
	cin >> n;
	string max = "1814/09/06";
	string min = "2014/09/06";
	string maxname = min, minname = max;
	string n1, n2;
	int count = 0;
	for(int i = 0; i < n; i++) {
		string s, day;
		cin >> s >> day;
		if(day >= max && day <= min) {
			count++;
			if(day <= maxname) {
				n1 = s;
				maxname = day;
			}
			if(day >= minname){
				minname = day;
				n2 = s;
			}
		}
	}
	if(count == 0) {
		cout << count;
	} else {
		cout << count << " " << n1 << " " << n2;	
	}
	return 0;
}