kulfi :
How to use invert match with awk like grep -v , i have below pattern mix of awk, sed, grep and sort.
Is there a pure awk or sed way to do the below..
$ awk '/status=sent/{print $1,$2,$7,$8|"sort -u"}' /var/log/maillog-20150308 |sed 's/to=<//g' | sed 's/>,//g' | grep -v "relay=local"
Sample log..
Mar 15 09:00:12 testhost postfix/local[11995]: 7245441DF1: to=<[email protected]>, relay=local, delay=0.02, delays=0/0/0/0.02, dsn=2.0.0, status=sent (delivered to file: /dev/null)
Mar 15 09:00:12 testhost postfix/local[11995]: 7245441DF1: to=<[email protected]>, relay=mysmtp.com, delay=0.02, delays=0/0/0/0.02, dsn=2.0.0, status=sent (delivered to file: /dev/null)
Current and desired Output:
$ awk '/status=sent/{print $1,$2,$7,$8|"sort -u"}' /tmp/test |sed 's/to=<//g' | sed 's/>,//g' | grep -v "relay=local"
Mar 15 [email protected] relay=mysmtp.com,
Mar 7 [email protected] [email protected]
James Brown :
This is one way of doing it:
$ awk '
$12=="status=sent" && $8!="relay=local," { # process only matching records
gsub(/^to=<|>,$/,"",$7) # tune that $7
b=$1 OFS $2 OFS $7 OFS $8 # buffer output record for
if(!a[b]++) # ... uniq record
print b # ... output
}' file
Output with given sample data:
Mar 15 [email protected] relay=mysmtp.com,
Updated with a one-liner version:
$ awk '$12=="status=sent"&&$8!="relay=local,"{gsub(/^to=<|>,$/,"",$7);b=$1 OFS $2 OFS $7 OFS $8;if(!a[b]++)print b}' file
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