How can I convert the date "Mon Jul 01 08:00:00 IST 2019
" of type string to ISODate "2019-07-01T03:00:00.000Z
"?
Update: Using DateTimeFormat, introduced in java 8:
The idea is to define two formats: one for the input format, and one for the output format. Parse with the input formatter, then format with the output formatter.
Your input format looks quite standard, except the trailing Z
. Anyway, let's deal with this: "yyyy-MM-dd'T'HH:mm:ss.SSS'Z'"
. The trailing Z
is the interesting part. Usually there's time zone data here, like -0700
. So the pattern would be ...Z,
i.e. without apostrophes.
The output format is way more simple: "dd-MM-yyyy"
. Mind the small y -s
.
Here is the example code:
DateTimeFormatter inputFormatter = DateTimeFormatter.ofPattern("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'", Locale.ENGLISH);
DateTimeFormatter outputFormatter = DateTimeFormatter.ofPattern("dd-MM-yyy", Locale.ENGLISH);
LocalDate date = LocalDate.parse("2018-04-10T04:00:00.000Z", inputFormatter);
String formattedDate = outputFormatter.format(date);
System.out.println(formattedDate); // prints 10-04-2018
Original answer - with old API SimpleDateFormat
SimpleDateFormat inputFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'");
SimpleDateFormat outputFormat = new SimpleDateFormat("dd-MM-yyyy");
Date date = inputFormat.parse("2018-04-10T04:00:00.000Z");
String formattedDate = outputFormat.format(date);
System.out.println(formattedDate); // prints 10-04-2018