math black hole

数学黑洞
Time Limit: 1500 ms Memory Limit: 65536 KiB
Submit Statistic
Problem Description

Any 4-digit natural number N (N cannot be the same as 4 numbers, such as 1111, 2222, ....9999 is not allowed, and N cannot be 6174), rearrange the 4 numbers that make up the natural number N to form a maximum number When subtracting the minimum number, the maximum number and the minimum number, the difference is still a natural number. Rearrange the numbers of the difference to form a maximum number and a minimum number. When the maximum number and the minimum number are subtracted, the difference is still a natural number. Repeat until the difference is a mysterious number 6174 (mathematical black hole).
Input

There are multiple groups of input data, each group occupies a row, and each row contains a 4-digit natural number N. Input files until EOF!
Output

For each set of input, the output has 2 lines. The first line is all the differences, separated by spaces, and there are spaces after the last number; the second line is the number of differences.
Sample Input

1000
1500
3000
Sample Output

999 8991 8082 8532 6174
5
5085 7992 7173 6354 3087 8352 6174
7
2997 7173 6354 3087 8352 6174
6
Hint

Source

zlh

package sdut;

import java.util.Scanner;
//import java.util.Arrays;
class heidong{
    int n;
    final int mm = 4;
    heidong(int n){
        this.n = n;
    }
    int a[] = new int[mm];
    void sort(){
        int t;
        for(int i = 0; i < mm - 1; i++){
            for(int j = 0; j < mm - i - 1; j++){
                if(a[j] > a[j+1]){
                    t = a[j];
                    a[j] = a[j + 1];
                    a[j+1] = t;
                }
            }
        }
    }
    void fenjie(){
        int i = 0;
        while(n > 0){
            a[i++] = n % 10;
            n /= 10;
        }

    }
}

public class Main {

    public static void main(String[] args) {
        Scanner ss = new Scanner(System.in);
        int n;
        while(ss.hasNextInt()){
            n = ss.nextInt();
        }
        ss.close();
    }

}