~~~How can the writing style end in a dull way, and the story does not recognize ordinary at the beginning ✌✌✌
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topic:
Problem solving ideas:
>由于题目要求算法的空间复杂度为O(1),所以肯定是不能开辟新的数据进行复制的
>所以这里定义个临时变量,用于保存当前值
>不断交换首尾对应位置的元素
>由于首尾对称,所以只需要循环表长的一半
Code:
#include <iostream>
using namespace std;
#define Maxsize 50
// 定义顺序表结构
typedef struct
{
int data[Maxsize];
int length = 0;
} SqList;
// 插入测试数据
void ListInsert(SqList &L)
{
int val = 0;
while (cin >> val)
{
L.data[L.length++] = val;
if (cin.get() == '\n')
{
break;
}
}
}
// 打印顺序表
void PrintList(SqList L)
{
for (int i = 0; i < L.length; i++)
{
cout << L.data[i] << '\t';
}
cout << endl;
}
// 题目功能函数
void ReverseList(SqList &L)
{
int temp = 0;
for (int i = 0; i < L.length / 2; i++)
{
temp = L.data[i]; // 定义临时变量保存当前位置的值
// 将首尾对应位置进行交换
L.data[i] = L.data[L.length - i - 1];
L.data[L.length - i - 1] = temp;
}
}
int main()
{
SqList L; // 创建一个顺序表
ListInsert(L); // 插入写测试数据
PrintList(L);
ReverseList(L);
PrintList(L);
}