LeetCode--Custom Sort String

Ideas:

    Convert T to an array, traverse the array, swap the position to match S, and skip the characters that are not in S.

class Solution {
    public String customSortString(String S, String T) {
        char[] T_arr=T.toCharArray();
        for(int i=0;i<T_arr.length;i++){
            if(S.indexOf(T_arr[i])==-1){
                continue;
            }
            for(int j=i;j<T_arr.length;j++){
                if(S.indexOf(T_arr[j])==-1){
                    continue;
                }
                if(S.indexOf(T_arr[i])>S.indexOf(T_arr[j])){
                    char tmp=T_arr[i];
                    T_arr[i]=T_arr[j];
                    T_arr[j]=tmp;
                }
            }
        }

        return String.valueOf(T_arr);
    }
}