STEP1、using Newtonsoft.Json.Linq;
STEP2 How to get an attribute (node) value in json, delete it, add it
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//2.1 数组用JArray加载
string
jsonText =
"[{'a':'aaa','b':'bbb','c':'ccc'},{'a':'aa','b':'bb,'c':'cc'}]"
;
var
mJObj = JArray.Parse(jsonText);
//需求，删除列表里的a节点的值为'aa'的项
IList<JToken> delList =
new
List<JToken>();
//存储需要删除的项
foreach
(
var
ss
in
mJObj )
//查找某个字段与值
{
if
(((JObject) ss)[
"a"
]==
"aa"
)
delList .add(ss);
}
foreach
(
var
item
in
delList )
//移除mJObj 在delList 里的项
{
mJObj .remove(item);
}
//2.2 非数组用JObject加载 （这里主要以这个为例子）
string
jsonText =
"[{'a':'aaa','b':'bbb','c':'ccc'}]"
;
var
mJObj = JObject.Parse(jsonText t);
mJObj.Add()
//新增，没试过
var
v1=mJObj[a].ToString()
//得到'aaa'的值
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The above examples can be used interactively and flexibly
Note, JArray can only be used to find the object of the indexed item. To find the object, you need to convert it to JObject, and then find the corresponding property value.
其他写法补充
1、属性下嵌套json （非数组）遍历其包含的属性列表
var xx = ((mJObj["dim"])).Children().Values();
foreach (var item in xx)
{
var dimID = ((JObject) item)["id"];
}