Usage of delphi format

1. The usage of the Format function
Format is a very common, but it seems annoying method. I try to translate the help of this method so that it has a complete overview for everyone to query:

First look at its declaration:
function Format(const Format: string; const Args: array of const): string; overload;
In fact, the Format method has two forms, and the other has three parameters. The main difference is that it is Thread-safe, but not much use, so only the first one is introduced here:

function Format(const Format: string; const Args: array of const): string; overload;
The Format parameter is a format string used to format the value in Args. What is Args, it is a variant array, that is, it can have multiple parameters in it, and each parameter can be different.
Such as the following example:
Format('my name is %6s',['wind']);
after the return is
my name is wind

Now let's look at the details of the Format parameter:
Format can write ordinary strings, such as 'my name is', but some format command characters have special meanings, such as "%6s"

The format directive has the following form:
"%" [index ":"] ["-"] [width] ["." prec] type
It starts with "%" and ends with type, which indicates a specific type . The middle is the instruction character used to format the type type, which is optional.

Let's first look at type, type can be the following characters:
d decimal number, indicating an integer value
u is an integer value like d, but it is unsigned, and if its corresponding value is negative, it returns When is a 2 to the 32nd power minus the absolute value of the number
   such as: Format('this is %u',[-2]);
   The return is: this is 4294967294
f corresponds to the floating point number
e scientific notation, corresponds to the integer Type numbers and floating-point numbers,
   such as Format('this is %e',[-2.22]);
   returns: this is -2.22000000000000E+000
   Wait a minute and then explain that if the precision of the number is reduced by
g, this can only correspond to floating-point numbers type, and it will remove the redundant number in the value,
   such as Format('this is %g',[02.200]);
   The return is: this is 2.2
n can only correspond to floating-point type, and convert the value into the form of a number. Looking at an example, you can understand
   Format('this is %n',[4552.2176]);
   what is returned is this is 4,552.22
   Note that there are two points, one is that it is only expressed to two decimal places, wait a moment to talk about how to eliminate this situation
   two Yes, even if the decimal is not truncated, it will not also have a comma to separate the m coin type like the integer part
, but there is a better way to format the currency type, here is just simple formatting
   Also it only corresponds to float point value
   Format('this is %m',[9552.21]);
Return: this is $9,552.21
p corresponds to the pointer type, the returned value is the address of the pointer, expressed in hexadecimal form, for
   example:
   var X:integer;
     p:^integer;
   begin
    X:=99;
    p:=@X;
    Edit1.Text:=Format('this is %p',[p]);
   end;
   The content of Edit1 is: this is 0012F548
s corresponds to the string Type, needless to say,
x must be an integer value, returned in hexadecimal form
   Edit1.Text:=Format('this is %X',[15]); The
   return is: this is F

After the type is described, the instructions for formatting Type are described below:
[index ":"] How to express this, see an example
             Format('this is %d %d',[12,13]);
             the first % The index of d is 0, and the second %d is 1, so the characters are displayed
             like this this is 12 13

             而如果你这样定义:
             Format('this is %1:d %0:d',[12,13]);
             那么返回的字符串就变成了
             this is 13
12
             现在明白了吗,[index ":"] 中的index指示Args中参数显示的
             顺序

             还有一种情况,如果这样Format('%d %d %d %0:d %d', [1, 2, 3, 4])
             将返回1 2 3 1 2。
             如果你想返回的是1 2 3 1 4,必须这样定:
             Format('%d %d %d %0:d %3:d', [1, 2, 3, 4])
             但用的时候要注意,索引不能超出Args中的个数,不然会引起异常
             如Format('this is %2:d %0:d',[12,13]);
             由于Args中只有12 13 两个数,所以Index只能是0或1,这里为2就错了
[width] 指定将被格式化的值占的宽度,看一个例子就明白了
         Format('this is %4d',[12]);
         输出是:this is    12
         这个是比较容易,不过如果Width的值小于参数的长度,则没有效果。
         如:Format('this is %1d',[12]);
         输出是:this is 12
["-"]   这个指定参数向左齐,和[width]合在一起最可以看到效果:
        Format('this is %-4d,yes',[12]);
        输出是:this is 12    ,yes
        
["." prec] 指定精度,对于浮点数效果最佳:
            Format('this is %.2f',['1.1234]);
            输出 this is 1.12
            Format('this is %.7f',['1.1234]);
            输了 this is 1.1234000

            而对于整型数,如果prec比如整型的位数小,则没有效果反之比整形值的位数大,则会在整型值的前面以0补之
            Format('this is %.7d',[1234]);
            输出是:this is 0001234]
          
            对于字符型,刚好和整型值相反,如果prec比字符串型的长度大则没有效果,反之比字符串型的长度小,则会截断尾部的字符
            Format('this is %.2s',['1234']);
            输出是 this is 12
           
            而上面说的这个例子:
            Format('this is %e',[-2.22]);
            返回的是:this is -2.22000000000000E+000
            怎么去掉多余的0呢,这个就行啦
            Format('this is %.2e',[-2.22]);

二 FormatDateTime的用法
他的声明为:
function FormatDateTime(const Format: string; DateTime: TDateTime): string; overload;
当然和Format一样还有一种,但这里只介绍常用的第一种
Format参数是一个格式化字符串。DateTime是时间类型。返回值是一种格式化后的字符串

重点来看Format参数中的指令字符
c 以短时间格式显示时间,即全部是数字的表示
   FormatdateTime('c',now);
   输出为:2004-8-7 9:55:40
d 对应于时间中的日期,日期是一位则显示一位,两位则显示两位
   FormatdateTime('d',now);
   输出可能为1~31
dd 和d的意义一样,但它始终是以两位来显示的
   FormatdateTime('dd',now);
    输出可能为01~31
ddd 显示的是星期几
    FormatdateTime('ddd',now);
    输出为: 星期六
dddd 和ddd显示的是一样的。
    但上面两个如果在其他国家可能不一样。
ddddd 以短时间格式显示年月日 
     FormatdateTime('ddddd',now);
     输出为:2004-8-7
dddddd 以长时间格式显示年月日
     FormatdateTime('dddddd',now); 
     输出为:2004年8月7日
e/ee/eee/eeee 以相应的位数显示年
      FormatdateTime('ee',now); 
     输出为:04   (表示04年)
m/mm/mmm/mmmm 表示月
      FormatdateTime('m',now);
      输出为:8
      FormatdateTime('mm',now);
      输出为   08
      FormatdateTime('mmm',now);
      输出为   八月
      FormatdateTime('mmmm',now); 
      输出为   八月
     和ddd/dddd 一样,在其他国家可能不同
yy/yyyy 表示年
      FormatdateTime('yy',now);
      输出为 04
      FormatdateTime('yyyy',now);
      输出为 2004
h/hh,n/nn,s/ss,z/zzz 分别表示小时,分,秒,毫秒
t   以短时间格式显示时间
      FormatdateTime('t',now);
     输出为 10:17
tt 以长时间格式显示时间
      FormatdateTime('tt',now);
      输出为10:18:46
ampm 以长时间格式显示上午还是下午
      FormatdateTime('ttampm',now);
      输出为:10:22:57上午

大概如此,如果要在Format中加普通的字符串,可以用双引号隔开那些特定义的字符,这样普通字符串中如果含特殊的字符就不会被显示为时间格式啦:
FormatdateTime('"today is" c',now);
输出为:today is 2004-8-7 10:26:58
时间中也可以加"-"或"/"来分开日期:
FormatdateTime('"today is" yy-mm-dd',now);
FormatdateTime('"today is" yy/mm/dd',now);
输出为: today is 04-08-07
也可以用":"来分开时间  
FormatdateTime('"today is" hh:nn:ss',now);
输出为:today is 10:32:23

三.FormatFloat的用法

常用的声明:
function FormatFloat(const Format: string; Value: Extended): string; overload;
和上面一样Format参数为格式化指令字符,Value为Extended类型为什么是这个类型,因为它是所有浮点值中表示范围最大的,如果传入该方法的参数比如Double或者其他,则可以保存不会超出范围。

关键是看Format参数的用法
0   这个指定相应的位数的指令。
    比如:FormatFloat('000.000',22.22);
    输出的就是022.220
    注意一点,如果整数部分的0的个数小于Value参数中整数的位数,则没有效果
    如:FormatFloat('0.00',22.22);
    输出的是:22.22
    但如果小数部分的0小于Value中小数的倍数,则会截去相应的小数和位数
    如:FormatFloat('0.0',22.22);
    输出的是:22.2
   
    也可以在整数0中指定逗号,这个整数位数必须大于3个,才会有逗号出现
    FormatFloat('0,000.0',2222.22);
    输出是:2,222.2
    如果这样FormatFloat('000,0.0',2222.22);
    它的输出还是:2,222.2
    注意它的规律

#   和0的用法一样,目前我还没有测出有什么不同。
    FormatFloat('##.##',22.22);
    输出是:22.00

E   科学表示法,看几个例子大概就明白了
    FormatFloat('0.00E+00',2222.22);
    输出是 2.22E+03
    FormatFloat('0000.00E+00',2222.22);
    输出是 2222.22E+00
     FormatFloat('00.0E+0',2222.22);
    22.2E+2
    明白了吗,全靠E右边的0来支配的。

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