[copy title]:
You are given two arrays (without duplicates) nums1
and nums2
where nums1
’s elements are subset of nums2
. Find all the next greater numbers for nums1
's elements in the corresponding places of nums2
.
The Next Greater Number of a number x in nums1
is the first greater number to its right in nums2
. If it does not exist, output -1 for this number.
Example 1:
Input: nums1 = [4,1,2], nums2 = [1,3,4,2]. Output: [-1,3,-1] Explanation: For number 4 in the first array, you cannot find the next greater number for it in the second array, so output -1. For number 1 in the first array, the next greater number for it in the second array is 3. For number 2 in the first array, there is no next greater number for it in the second array, so output -1.
Example 2:
Input: nums1 = [2,4], nums2 = [1,2,3,4]. Output: [3,-1] Explanation: For number 2 in the first array, the next greater number for it in the second array is 3. For number 4 in the first array, there is no next greater number for it in the second array, so output -1.
[brute force solution]:
Time analysis:
Space Analysis:
[Optimized]:
Time analysis:
Space Analysis:
[Wonderful output conditions]:
[Wonderful corner case]:
[Thinking question]:
[One sentence idea]:
[Input amount]: Empty: Normal situation: Extra large: Extra small: Special situations handled in the program: Abnormal situations (Illegal and unreasonable input):
[Paint]:
[One brush]:
[Second brush]:
[Three brushes]:
[Four brushes]:
[Five brushes]:
[Results of five-minute naked eye debug]:
[Summarize]:
[Complexity]: Time complexity: O( ) Space complexity: O( )
[English data structures or algorithms, why not use other data structures or algorithms]:
[Key templating code]:
[Other solutions]:
[Follow Up]:
Next Greater Element II still uses stack
[The topics given by LC change and change]:
[Code style]: