The meaning of the question: use 1, +, *, (,). These four symbols form an expression to express the number s (0 <= s <= 10000), and the number of 1s when 1 is the least
State transition equation: dp[i] = min(dp[i-1] + 1, dp[j] + dp[ij]);
Code:
#include<bits/stdc++.h> using namespace std; const int N = 100001; int dp[N]; int main() { fill(dp, dp + N, 10000); dp[0] = 0; dp[1] = 1; for(int i = 2; i <= 10000; i++) { int t = (int)sqrt(i); dp[i] = dp[i-1] + 1; for(int j = i - 1; j >= t; j--) { if(i % j == 0) dp[i] = min(dp[i], dp[j] + dp[i/j]); } } int n; while(scanf("%d", &n) != EOF) { printf("%d\n", dp[n]); } return 0; }