Implementation example of python nested dictionary comparison value and value
This article introduces python nested dictionary comparison values, values, and sharing them for your reference and learning through examples. Let's take a look at the detailed introduction together.
Example code
#value import types
allGuests = {'Alice': {'apples': 5, 'pretzels': {'12':{'beijing':456}}},
'Bob': {'ham sandwiches': 3, 'apple': 2},
'Carol': {'cups': 3, 'apple pies': 1}}
def dictget(dict1,obj,default=None):
for k,v in dict1.items() :
if k == obj:
print(v)
else:
if type(v) is dict:
re=dictget(v,obj)
if re is not default:
print(re)
dictget(allGuests,'beijing')
result:
Comparison of size
result:
Get the value of a key in the case of a python dictionary nested dictionary
Just recently, I was writing a test program for an interface in python, during which I used to parse a dictionary to get the value of a certain key, because the format of the dictionary returned by multiple interfaces is not fixed and there are multiple levels of nesting. In the dictionary method, I didn't find a method that can directly achieve the purpose, so I wrote a program myself. Share with everyone:
#coding: utf-8
import types
#Get the value corresponding to objkey in the dictionary, suitable for dictionary nesting
#dict:dictionary
#objkey:target key
#default:default value returned when not found
def dict_get(dict, objkey, default):
tmp = dict
for k,v in tmp.items():
if k == objkey:
return v
else:
if type(v) is types.DictType:
ret = dict_get(v, objkey, default)
if ret is not default:
return ret
return default #such
as
dicttest={"result":{"code":"110002","msg":"device serial number or verification code error"}}
ret=dict_get(dicttest, 'msg' , None)
print(ret)
Summary
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