Python dictionary key returns a value, lambda function

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Dictionary type sort transcripts

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Method I. dictionary key value returned by

data1 = {"lili":80, "xiaoqiang":75, "yunyun":89, "yuanyuan":90, "wanghao":85}
list1 = []
list2 = []
for key, value in data1.items():
    list1.append(key)
    list1.append(value)
    list2.append(value)


list2 = sorted(list2,reverse = True)
for i in range(len(list2)):
    j = list1.index(list2[i]) # 字典通过值返回键
    print("{}:{}".format(list1[j-1], list2[i]))

Output Effect:

Method II.

data1 = {"lili":80, "xiaoqiang":75, "yunyun":89, "yuanyuan":90, "wanghao":85}
ls = list(data1.items()) # 列表嵌套元组
print(ls)
ls.sort(key = lambda x:x[1], reverse = True)
for i in range(5):
    print("{}:{}".format(ls[i][0], ls[i][1]))

Output effect: