Calculator Matrix Flip

Xiaomeng is currently working on an application that flips pictures. As you may know, pictures are actually made up of dots. So Xiaomeng wanted to make a program that could flip the matrix first to solve the core part of his problem.

input format

The first line of input consists of integers M,N,T(0<N,M<200)M,N,T(0<N,M<200) separated by spaces$M,N,T(0<N,M<200)$，$The\; value\; of\; T$ is$0$ or$1$ . where$M$ and$N$ represents the number of rows and columns of the matrix to be processed, respectively,$T$ is$When\; 0$ means flip left and right, it is$1$ means upside down.

MM after$M$ lines, each line includes NNseparated by spaces$N$ integers, sequentially the data for each row of the input matrix.

output format

Output includes $M$ rows$N$ columns, each number is separated by a space, and there is a spaceat the end of each row, which represents the matrix after being flipped as required.

sample input

4 4 1
1 2 3 4
5 6 7 8
9 0 1 2
3 4 5 6

Sample output

3 4 5 6
9 0 1 2
5 6 7 8
1 2 3 4

#include<iostream>

using namespace std;

intmain()
{
    int M,N,T,i,j,x;
    cin>>M>>N>>T;
    int a[200][200];
    for (i=0;i<M;i++){
        for (j=0;j<N;j++)
            cin>>a[i][j];
    }
    
    if (T==0){
        for (i=0;i<M;i++){
           for (j=N-1;j>=0;j--) {
               cout<<a[i][j]<<" ";
               if(j%N==0)
                   cout<<endl;
           }
        }

    }
    
    if (T==1){
       for(i=M-1;i>=0;i--){
           for (j=0;j<N;j++){
               cout<<a[i][j]<<" ";
               if((j+1)%N==0)
                   cout<<endl;}
       }
    }
    return 0;
}