How to store distinct characters of a string

Shivam Sharma :

public class NoDuplicate { 
    static final int NO_OF_CHARS = 256; 

    /* Print duplicates present in the passed string */
    static void printDistinct(String str) 
    { 
        // Create an array of size 256 and count of 
        // every character in it 
        int[] count = new int[NO_OF_CHARS]; 

        /* Count array with frequency of characters */
        int i; 
        for (i = 0; i < str.length(); i++) 
            if(str.charAt(i)!=' ') 
                count[(int)str.charAt(i)]++; 
        int n = i; 

        // Print characters having count more than 0 
        for (i = 0; i < n; i++) 
            if (count[(int)str.charAt(i)] == 1) 
                System.out.print(str.charAt(i)); 
    } 

    /* Driver program*/
    public static void main(String args[]) 
    { 
        String str = "SHINCHAN"; 
        printDistinct(str); 
    } 
} 

I am trying to store the distinct characters in a string. The problem is that my code remove all duplicate elements. Example:

Input: SHINCHAN

Actual output: SICA

Desired output: SHINCA (I want to store each element once)

Nicholas K :

You can make use of a LinkedHashSet to implement the same :

static void printDistinct(String str) {
    Set<Character> origSet = new LinkedHashSet<Character>();
    StringBuilder concat = new StringBuilder();
    for (int i = 0; i < str.length(); i++) {
        if (origSet.add(str.charAt(i))) {
            concat.append(str.charAt(i));
        }
    }
    System.out.println(concat);
}

---

If you are using java-8, you can just do :

str.chars().mapToObj(e -> Character.toString((char) e))
           .distinct()
           .forEach(System.out::println);