Currency conversion (special case consideration)

Code:

#include<iostream>
#include<cmath>
#include<algorithm>
#include<cstring>
#include<string>
#include<stack>
using namespace std;
char zhuanhuan(char x)
{
    if(x=='0')
        x='a';
    else if(x=='1')
        x='b';
    else if(x=='2')
        x='c';
    else if(x=='3')
        x='d';
    else if(x=='4')
        x='e';
    else if(x=='5')
        x='f';
    else if(x=='6')
        x='g';
    else if(x=='7')
        x='h';
    else if(x=='8')
        x='i';
    else if(x=='9')
        x='j';
    return x;

}
string zhuanhuann(int c)
{
    string ss;
    if(c==1)
        ss="";
    else if(c==2)
        ss="S";
    else if(c==3)
        ss="B";
    else if(c==4)
        ss="Q";
    else if(c==5)
        ss="W";
    else if(c==6)
        ss="SW";
    else if(c==7)
        ss="BW";
    else if(c==8)
        ss="QW";
    else if(c==9)
        ss="Y";
    return ss;
}
int main()
{
    string s;
    cin>>s;
    if(s.size()==1)
    {
        char c=zhuanhuan(s[0]);
        cout<<c<<endl;
        return 0;
    }
    int len=s.size();
    int x=s.rfind("0");
    while(x==s.size()-1)
    {
        s.erase(x,1);
        //printf("%d ",x);
        x=s.rfind("0");
    }
    //cout<<endl;
    for(int i=0; i<s.size(); i++)
    {
        char c=zhuanhuan(s[i]);
        string cc=zhuanhuann(len-i);
        if(cc=="SW")
        {
            int xx=i+1;
            if(s[i+1]!='0'&&xx<s.size())
                cc="S";
        }
        if(cc=="BW")
        {
            int xx=i+2;
            if((s[i+1]!='0'||s[i+2]!='0')&&xx<s.size())
                cc="B";
        }
        if(cc=="QW")
        {
            int xx=i+3;
            if((s[i+1]!='0'||s[i+2]!='0'||s[i+3]!='0')&&xx<s.size())
                cc="Q";
        }
        if(s[i]!='0')
        {
            cout<<c<<cc;
        }
        else if(i>0&&s[i-1]!='0')
        {
            cout<<c;
        }
    }
}
/*
1.个位数
2.除了第一位其他位都是0
3.105045008这种间断的数，对十万，百万，千万还是一百五十万这种数据类型的考察