Missing space when using sed

RogerRab2020 :

So I'm using lsof in combination with jq to convert to json. The original output example:

  [
    "blah",
    "1234",
    "yoda",
    "561u",
    "IPv4",
    "297229000",
    "0t0",
    "TCP",
    "15.60.74.17:1511",
    "(LISTEN)"
  ]
]

When using this with sed as:

sed -e "s/(//" -e "s/)//" | sed 's/.*:\([0-9]\+\).*/"\1",/g'

The output comes out as:

  [
    "blah",
    "1234",
    "yoda",
    "561u",
    "IPv4",
    "297229000",
    "0t0",
    "TCP",
"1511",
    "LISTEN"
  ]
]

Notice the space is not kept for "1511" not sure what i'm missing, i'm sure something silly, anyone know what i'm missing here?

dstromberg :

You could use a register, but it's easier to just match less:

echo '    "15.60.74.17:1511",' | sed -e "s/(//" -e "s/)//" -e 's/[0-9\.]*:\([0-9]\+\).*/\1",/g'

BTW, you don't need 2 sed's - just one with two -e's.