vue+element 身份证号码以及有效性校验 适用 15位 或18位

  data () {
    let idCardValidity = (rule, code, callback) => {
      var city = { 11: "北京", 12: "天津", 13: "河北", 14: "山西", 15: "内蒙古", 21: "辽宁", 22: "吉林", 23: "黑龙江 ", 31: "上海", 32: "江苏", 33: "浙江", 34: "安徽", 35: "福建", 36: "江西", 37: "山东", 41: "河南", 42: "湖北 ", 43: "湖南", 44: "广东", 45: "广西", 46: "海南", 50: "重庆", 51: "四川", 52: "贵州", 53: "云南", 54: "西藏 ", 61: "陕西", 62: "甘肃", 63: "青海", 64: "宁夏", 65: "新疆", 71: "台湾", 81: "香港", 82: "澳门", 91: "国外 " };
      var tip = ""
      var pass = true

      if (!code || !/^\d{6}(18|19|20)?\d{2}(0[1-9]|1[012])(0[1-9]|[12]\d|3[01])\d{3}(\d|X)$/i.test(code)) {
        tip = "身份证号格式错误"
        pass = false;
      } else if (!city[code.substr(0, 2)]) {
        tip = "地址编码错误"
        pass = false
      } else {
        // 18位身份证需要验证最后一位校验位
        if (code.length === 18) {
          code = code.split('')
          // ∑(ai×Wi)(mod 11)
          // 加权因子
          var factor = [7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2]
          // 校验位
          var parity = [1, 0, 'X', 9, 8, 7, 6, 5, 4, 3, 2]
          var sum = 0
          var ai = 0
          var wi = 0
          for (var i = 0; i < 17; i++) {
            ai = code[i]
            wi = factor[i]
            sum += ai * wi
          }
          var last = parity[sum % 11];
          if (parity[sum % 11] != code[17]) {
            tip = "校验位错误"
            pass = false
          }
        }
      }
      if (!pass) {
        callback(new Error(tip))
      } else {
        callback()
      }
      // if (!pass) alert(tip)
      // return pass
    }
    return {
     
      personInfo: {
        idCard: "",
      },
      rules: {
        idCard: [{ required: true, message: '请输入证件号', trigger: 'blur' },
          {
            pattern: /(^\d{8}(0\d|10|11|12)([0-2]\d|30|31)\d{3}$)|(^\d{6}(18|19|20)\d{2}(0\d|10|11|12)([0-2]\d|30|31)\d{3}(\d|X|x)$)/,
            message: '请输入正确的证件号'
          },
          { validator: idCardValidity, trigger: 'blur' }],
      }
    }
  },

1.规则方法写在 data里 return之前。

2. 身份证有效性校验规则来源与百度

校验公示:∑(ai×Wi)(mod 11)

https://baike.baidu.com/item/%E6%9C%89%E6%95%88%E8%BA%AB%E4%BB%BD%E8%AF%81%E4%BB%B6/5039723?fr=aladdin

 

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Origin blog.csdn.net/qq_31173561/article/details/101273159