OJ-1052: 数列求和4 (a+aa+aaa+…aa…a(n个a)的和)、java

题目描述

输入n和a,求a+aa+aaa+…aa…a(n个a),如当n=3,a=2时,2+22+222的结果为246

输入

包含两个整数,n和a,含义如上述,你可以假定n和a都是小于10的非负整数

输出

输出前n项和,单独占一行

样例输入

3 2

样例输出

246

代码示例

import java.util.*;
public class Main{
    
    
	public static void main(String[] args){
    
    
		Scanner sc = new Scanner(System.in);
		int n = sc.nextInt();
		int a = sc.nextInt();
		int num = a;
		int result = a;
		for (int i=1; i<n; i++) {
    
    
			num += a * Math.pow(10,i);
			result += num;
		}
		if (n == 0) {
    
    
			result = 0;
		}
		System.out.println(result);
	}
}

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Origin blog.csdn.net/weixin_43796109/article/details/109468751
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