(C language) Input two integers a and n, and calculate the value of the following expression. Sn=a+aa+aaa+aaaa+…+aa…aa(n a)
method one:
#include<stdio.h>
#include<stdlib.h>
int main(){
int a,n,sum,temp=0;
printf("请输入数字a和n:");
scanf("%d %d",&a,&n);
for(int j=0;j<n;j++){
temp=temp*10+a;
sum=sum+temp;
}
printf("计算结果为:Sn=%d",sum);
}
Method Two:
#include<stdio.h>
#include<stdlib.h>
#include<math.h>
int calculate(int a,int n){
int s=0;
for(int i=1;i<n;i++){
s=s+a*pow(10,i);
}
s=s+a;
return s;
}
int main(){
int a,n,sum=0;
printf("请输入整数a和n: ");
scanf("%d %d",&a,&n);
for(int i=1;i<=n;i++){
sum=sum+calculate(a,i);
}
printf("计算结果为:Sn=%d",sum);
}