取出数组重复元素

more_AFIB_list = []
more_AFIB_index = [0]*(sumIndex[len(sumIndex)-1]+1)
for i in range(0,len(sumIndex)):
    more_AFIB_index[sumIndex[i]] += 1
for i in range(1,len(more_AFIB_index)):
    if(more_AFIB_index[i] > 1):
#         print(i)
        more_AFIB_list.append(i)
print(more_AFIB_list)
print(len(more_AFIB_list))

空间复杂度太高,哈希表可以降低空间复杂度,可惜不会,再议

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Origin blog.csdn.net/HJ33_/article/details/115920455