关于ajax通过按钮向servlet发请求更新数据库，第一次可以，第二次点击失效的问题

Others 2021-11-19 15:39:48 views: null

因为我把servlet连接数据库驱动的代码写到了servlet的init方法中，init方法只执行一次，所以servlet第二次执行ajax的doget或dopost请求时无法连接到服务器

解决方法：把servlet连接数据库的代码放到doget或dopost方法中

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Origin blog.csdn.net/qq_45835078/article/details/111030915
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