Original title link: Luogu link ; AtCoder link
Ideas
Each time according to the previous one, calculate the next one as TA-1/TA/TA+1, put it queue
in, and finally output the KKInteger popped K times.
Precautions
- No need to
long long
knowWA
! - The previous digit is 0 0When 0, the next digit cannot be− 1 -1− 1 ! (Special judgement)
- The previous digit was 9 9At 9 o'clock the next digit cannot be10 101 0 ! (Also special judgment)
Code
#include <cstdio>
#include <queue>
using namespace std;
typedef long long LL;
int main(int argc, char** argv)
{
int k;
scanf("%d", &k);
queue<LL> q;
for(int i=1; i<10; i++) q.push(i);
while(true)
{
LL x = q.front(); q.pop();
if(--k == 0)
{
printf("%lld\n", x);
return 0;
}
int r = x % 10LL;
x *= 10LL;
x += r;
if(r > 0) q.push(x - 1);
q.push(x);
if(r < 9) q.push(x + 1);
}
return 0;
}