Known proposition formula (¬p→q)→(¬q∨p)

Known proposition formula (¬ p → q) → (¬ q ∨ p) (\lnot p\rightarrow q)\rightarrow(\lnot q \lor p)(¬pq)(¬qp)

Construct truth table

p, ( ¬ p → q ) (\lnot p\rightarrow q) (¬pq) ( ¬ q ∨ p ) (\lnot q \lor p) (¬qp) ( ¬ p → q ) → ( ¬ q ∨ p ) (\lnot p\rightarrow q)\rightarrow(\lnot q \lor p) (¬pq)(¬qp)
0 ,0 0 1 1
0,1 1 0 0
1,0 1 1 1
1,1 1 1 1

Disjunctive paradigm

( ¬ p → q ) → ( ¬ q ∨ p ) (\lnot p\rightarrow q)\rightarrow(\lnot q \lor p) (¬pq)(¬qp)

( p ∨ q ) → ( ¬ p ∨ q ) (p\lor q)\rightarrow(\lnot p \lor q) (pq)(¬pq)

¬ ( p ∨ q ) ∨ ( ¬ p ∨ q ) \lnot(p\lor q)\lor(\lnot p \lor q) ¬(pq)(¬pq)

( ¬ p ∧ ¬ q ) ∨ ( ¬ q ∨ p ) (\lnot p \land \lnot q)\lor (\lnot q \lor p) (¬p¬q)(¬qp)

( ¬ p ∧ ¬ q ) ∨ ¬ q ∨ p (\lnot p\land \lnot q)\lor \lnot q\lor p (¬p¬q)¬qp

( ¬ p ∧ ¬ q ) ∨ ¬ q ∧ ( p ∨ ¬ p ) ∨ p ∧ ( q ∨ ¬ q ) (\lnot p\land \lnot q)\lor \lnot q\land(p\lor \lnot p)\lor p\land(q\lor \lnot q) (¬p¬q)¬q(p¬p)p(q¬q)

( ¬ p ∧ ¬ q ) ∨ ( ¬ q ∧ p ) ∨ ( ¬ q ∧ ¬ p ) ∨ ( p ∧ q ) ∨ ( p ∧ ¬ q ) (\lnot p\land \lnot q)\lor(\lnot q\land p)\lor (\lnot q\land \lnot p)\lor (p\land q)\lor(p\land \lnot q) (¬p¬q)(¬qp)(¬q¬p)(pq)(p¬q)

( ¬ p ∧ ¬ q ) ∨ ( ¬ q ∧ p ) ∨ ( p ∧ q ) (\lnot p\land \lnot q)\lor (\lnot q\land p)\lor(p\land q) (¬p¬q)(¬qp)(pq)

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Origin blog.csdn.net/qq_41870170/article/details/114839573