这是一道来自leetcode的简单题目,第一次接触到了使用异或运算符进行解答。
topic
Given an array of non-empty integers, except for an element that appears only once, every other element appears twice. Find the element that appears only once.
Brute force traversal
var singleNumber = function(nums){
let i = 0 ,j = 0 ;
for(i=0;i<nums.length;i++){
for(j=0;j<nums.length;j++){
if(i != j && nums[i] == nums[j]){
break;
};
};
if(j == nums.length){
return nums[i];
};
}
}
XOR operator to solve problems
/**
* @param {number[]} nums
* @return {number}
*/
var singleNumber = function(nums) {
for(let i=1;i<nums.length;i++){
nums[0] = nums[0] ^ nums[i];
}
return nums[0]
};