【problem】
Given a range of 1 ≤ a [i] ≤ n (n = size of the array) of an integer array, the array element number appears twice, others only once.
Find all numbers [1, n] does not appear between the range in the array.
You can not use the extra space and time complexity of this task is the case of O (n) do? You can not assume that the array returned in the extra space.
Input: [4,3,2,7,8,2,3,1] Output: [5,6]
[Code]
class Solution { public: vector<int> findDisappearedNumbers(vector<int>& nums) { for(int i = 0; i < nums.size(); i++) nums[abs(nums[i])-1] = -abs(nums[abs(nums[i])-1]); vector<int> res; for(int i = 0; i < nums.size(); i++) { if (nums[i] > 0) res.push_back(i+1); } return res; } };