This question requires calculating f(x)
the value of the following piecewise function :
y = f (x) = {xx != 10 1 / xx = 10 y = f(x) = \begin{cases} x& \text{x != 10}\ \1/x& \text{x = 10} \end{cases}Y=f(x)={
x1/xx != 10x = 10
Input format:
The input gives the real number x in one line.
Output format:
“f(x) = result”
Output in the format in one line , in which x and result both retain one decimal place.
Input example 1:
10
Output sample 1:
f(10.0) = 0.1
Input example 2:
234
Output sample 2:
f(234.0) = 234.0
Code:
# include <stdio.h>
# include <stdlib.h>
int main(){
double x,result;
scanf("%lf",&x);
if (x == 10) result = 1.0 / x;
else result = x;
printf("f(%.1lf) = %.1lf",x,result);
return 0;
}
Submit screenshot:
Problem-solving ideas:
Basic operation, the previous questions have already been explained ~ familiarity is fine