Number flip (string processing)

Digital flip

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Problem solving ideas

It's a very simple question

AC code

#include<cstdio>
using namespace std;
int n,ans;
int main()
{
    
    
	scanf("%d",&n);
	if(n<0)printf("-"),n=-n;//特判
	while(n!=0)//倒过来
	{
    
    
		ans=ans*10+n%10;
		n/=10;
	}
	printf("%d",ans);
	return 0;
}

Thank you

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Origin blog.csdn.net/weixin_45524309/article/details/113140773