HJ003 Obviously random number

table of Contents

 

Title description

Enter description

Output description

enter

Output

Description

Question ideas

AC code


Title description

Obviously he wanted to invite some students to do a questionnaire survey in school. For the objectivity of the experiment, he first generated N random integers between 1 and 1000 (N≤1000). For the repeated numbers, only Keep one and remove the rest of the same number. Different numbers correspond to different student numbers. Then sort these numbers from smallest to largest, and go to classmates to investigate in the order. Please help you clearly complete the work of "de-duplication" and "sorting" (there may be multiple sets of data in the same test case, I hope you can handle it correctly).

 

Note: The test case guarantees the correctness of the input parameters, and the answerer does not need to verify. There is more than one set of test cases.

When there is no new input, the input ends.

Enter description

Note: The input may have multiple sets of data. Each group of data consists of multiple rows, the first row first enter the number N of random integers, and the next N rows then enter the corresponding number of integers. Please see the "example" below for the specific format.

Output description

Return multiple rows, the processed result

Example 1

enter

3
2
2
1
11
10
20
40
32
67
40
20
89
300
400
15

Output

1
2
10
15
20
32
40
67
89
300
400

Description

Sample input explanation: The sample has two sets of tests. The first group is 3 numbers, namely: 2, 2, 1. The second group is 11 numbers, respectively: 10, 20, 40, 32, 67, 40, 20, 89, 300, 400, 15. 

Question ideas

Numbers within 1000 deduplicate + sort, no doubt, use bucket sort

AC code

#include<iostream>
using namespace std;

int main(){
    int N;
    int n;
    
    while(cin >> N){
        int num[1001] = {0};
    
        while(N--){
            cin >> n;
            num[n] = 1;
        }
        
        for(int i=0; i<1001; i++){
            if( num[i]==1 ){
                cout << i <<endl;
            }
        }
    }
    
    return 0;
}

 

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Origin blog.csdn.net/qq_40923413/article/details/113051611