Likou 1317. Convert an integer to the sum of two zero-zero integers

Title description

A "zero-zero integer" is a positive integer without any 0 in the decimal representation.

Give you an integer n, please return a list of two integers [A, B], satisfying:
A and B are zero-zero integers
A + B = n

The problem data guarantee at least one effective solution.
If there are multiple valid solutions, you can return to any one of them.

Example

示例 1:

输入:n = 2
输出:[1,1]
解释:A = 1, B = 1. A + B = n 并且 A 和 B 的十进制表示形式都不包含任何 0 。

示例 2:

输入:n = 11
输出:[2,9]

示例 3:

输入:n = 10000
输出:[1,9999]

示例 4:

输入:n = 69
输出:[1,68]

示例 5:

输入:n = 1010
输出:[11,999]

prompt

2 <= n <= 10^4

Problem solving ideas

Use a for loop to verify whether i and ni contain zero, if not, output

Code

/**
 * Note: The returned array must be malloced, assume caller calls free().
 */
bool ifnotHavezero(int num){
    
    
    if(num==0)return false;
    int temp=0;
    while(num){
    
    
        temp=num%10;
        num/=10;
        if(temp==0)return false;
    }return true;
}

int* getNoZeroIntegers(int n, int* returnSize){
    
    
     int *re=malloc(2*sizeof(int));
    *returnSize=2;
    for(int i=1;i<n;i++){
    
    
        if(ifnotHavezero(i)&&ifnotHavezero(n-i)){
    
    
            re[0]=i;
            re[1]=n-i;
            return re;
        } 
    }re[0]=-1;
    re[1]=-1;
    return re;
}

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Origin blog.csdn.net/qq_44722674/article/details/112725171