【Problem Solution】Move back the number

There are n integers in the title description , so the previous numbers are moved backward m positions, and the last m numbers become the previous m numbers. Write a function: To achieve the above function, input n numbers and output adjusted n numbers in the main function.
Input
the number of input data nn integers to move the position m
output
after the move n number

样例输入
10
1 2 3 4 5 6 7 8 9 10
2

样例输出
9 10 1 2 3 4 5 6 7 8 

---

Problem-solving ideas
First write an inverse function to exchange data in a given range
and then pass a total inverse function. First reverse the number before m, then reverse the number after m, and finally convert the whole Array transfer. Move back operation is complete.

---

#include <stdio.h>

//接收用户数据
void input_data(int* num, int n);

//逆置数组
void Reverse(int* num, int q, int p);

//总逆置
void convert(int* num, int n);

//输出数据
void put_data(int* num, int n);

int main(void){
    
    
    int num[20];
    //接收用户给定的数组大小
    int n;
    scanf("%d", &n);
    //调用函数实现功能
    input_data(num, n);
    convert(num, n);
    put_data(num, n);

    return 0;
}

//接收用户数据
void input_data(int* num, int n){
    
    
    //函数需要两个参数：*num 用来初始化的数组，n 数组的长度
	//接收用户数据
    for(int i = 0; i < n; i++)
        scanf("%d", &num[i]);
}

//逆置数组
void Reverse(int* num, int q, int p){
    
    
    int temp;
	//对指定范围内的数据进行互换
    for(; q < p; q++, p--){
    
    
        temp = num[q];
        num[q] = num[p];
        num[p] = temp;
    }
}

//总逆置
void convert(int* num, int n){
    
    
	//接收数据要后移的位置
    int m;
    scanf("%d", &m);
	//判断操作数据合法性
    if(m <= 0 || m >= n)    return;
    else{
    
    
    //下面有操作不同范围时，数组内的数据详情
        Reverse(num, 0, n - m - 1);
        Reverse(num, n - m, n - 1);
        Reverse(num, 0, n - 1);
    }
}

//输出数据
void put_data(int* num, int n){
    
    
    for(int i = 0; i < n; i++){
    
    
        printf("%d ", num[i]);
    }
}

---

Update progress this month

Creation is not easy, your likes are my biggest motivation! ! !
See you next time end~