Give you a string to find the top 10 most frequent characters

Mainly use HashMap, PriorityQueue (need to specify the sorting rules, sort according to the order from largest to smallest);

import java.util.*;

public class Main {
    
    

    public static void main(String[] args)  {
    
    
        String str = "helloffjjkfkjdfdsljfoijsgljslgasjgdjfjsdjfldghsojewfsf";
        char[] array = str.toCharArray();
        //记录字符个数
        HashMap<Character,Integer> map = new HashMap<>();
        for (int i = 0; i < array.length ; i++) {
    
    
            map.put(array[i],map.getOrDefault(array[i],0)+1);
        }
		
		//根据map的键值对Map.Entry<Chracter,Integer>的value值排序
        PriorityQueue<Map.Entry<Character,Integer>> ret = new PriorityQueue<>(10,
                (Map.Entry<Character,Integer> a,Map.Entry<Character,Integer> b)->{
    
    return b.getValue()-a.getValue();
        });
        
        for(Map.Entry<Character,Integer> ch:map.entrySet()){
    
    
            ret.offer(ch);
        }
        
        //打印输出
        while(!ret.isEmpty()){
    
    
            Map.Entry<Character,Integer> tmp =ret.poll();
            System.out.println(tmp.getKey()+" "+ tmp.getValue());
        }
    }

}

The interviewer said this is a relatively simple method, do you have any other methods?