Found through testing:
Run in Java language:
int i = 0;
i = i ++;
The value of i is 0;
Run in C language:
int i = 0;
i = i ++;
The value of i is 1;
Isn't it weird?
The reason is simple: C and Java use different operating mechanisms for ++!
In the Java language:
Use intermediate variable mechanism:
For example:
i = i++;
Is equivalent to:
temp = i;
i = i + 1;
i = temp;
Essence: In java, when performing an increment operation, a temporary variable is allocated,
++i: It will be assigned to temporary variables after adding 1;
i++: It will first assign a value to a temporary variable and then add 1";
The final use of the operation is not the variable itself, but the temporary variable that has been assigned a value.
In C language:
Self-increment mechanism:
int a = 0
int i = 0；
Figure out: a = i++ and i = i++; the results are different, why?
The i++ operation means to increment after returning the result.
The ++i operation means to increment before returning the result.
Then the result is obvious, a is 0, then why is i 1?
See the process: i = i++ => i = 0, i = i+1
i = 0 because the return value of i++ is 0, which is assigned
i = i+1 because i needs to increase!