C-Examples of array and pointer applications

1. Define the function

u8 CAN1_Send_Msg(u8 *msg)
{
    
    
	u8 b[4];
	for(i=0;i<4;i++)
	b[i] = msg[i];
	return 0;
}

2. Function call

u8 current_msg[4] = {
    
    ‘1’，‘2’，‘3’，“4”};
CAN1_Send_Msg(current_msg)；

First of all, let’s see that current_msg is the array name, so current_msg is equivalent to ¤t_msg[0].

For the defined function, we are equivalent to replacing msg with current_msg.
So that means *current_msg[i] is of type int. msg[i] is equivalent to current_msg[i].

The result of execution is b[0]='1', b[1]='2', b[2]='3', b[3]='4'.