Python dictionary structure sorting is converted into list and the first few items are taken

Dictionary data structure

Below is the dictionary data structure I need to process

{
    
    '一家': 0.026705843302086574, '三口': 0.03863159743158114, '搬家': 0.10736427147319758, '新家': 0.08690615802706024, '得来': 0.054637067219615684, '买来': 0.04612577908469612,..........,'新房子': 0.038974785884171845, '搬进': 0.09108143118667884}

Convert dictionary to list structure and sort

Sort according to the second field, which is the value.

   list = sorted(dict.items(), key=lambda d: d[1], reverse=True)

Here dict is to save the above data.
dict.items() is the list to be sorted;
key=lambdad: d[1] is the input d, and sorts the value of the second-dimensional data in the previous d.
The processed data is as follows:

[('东西', 0.13536804201443886), ('收拾', 0.11559750288801565), ('搬家', 0.10736427147319758)，..........., ('小东西', 0.0947239858845381), ('坟', 0.0929545414763724)] 

This is after the data has been converted into an ordered List structure, it is easy to fetch the data later.

Get the top 10 items

Here is a stupid way ~ traverse to take out the first 10 items, so if the data does not have 10 items, there will be no error.

        new_list = []
        num = 10
        for item in list:
            if num == 0:
                break
            else:
                new_list.append(item)
                num = num - 1

The web upload also passed list.sublist(end,start). I tried it and reported an error. I couldn't find the sublist method. I don't know what's wrong, so I just used the above method.


Big guys are welcome to criticize and correct!