Title description:
A description of Joseph's problem is:
n persons numbered 1, 2, ..., n sit in a circle in a clockwise direction, and each holds a password (a positive integer).
At the beginning, choose a positive integer as the upper limit m of the number of reports, starting from the first person in a clockwise direction and starting from 1 to report the number sequentially, and stop reporting the number when you report to m.
The person who reported m goes out, uses his password as the new value of m, and starts counting from 1 again from the next person in the clockwise direction, and so on, until everyone goes out.
Problem analysis:
Analyzing the problem, we can know that the Joseph Ring of Life and Death game can essentially be understood as the application of a circular singly linked list . Each person is equivalent to a node of the linked list. The realization of killing: delete the linked list node. Repeat the operation until the last person is out.
Function code:
void Initialise() //Initialize the linked list
void Traversal() //Traverse the linked list
void Delete() //Delete the node (to achieve killing)
Complete code:
#include<stdio.h>
#include<malloc.h>
#include<stdlib.h>
#include<string.h>
//定义结点
typedef struct LinkList
{
int data;
struct LinkList *next;
}node;
//初始化链表
void Initialise(node **pNode,int item)//**pNode 指向指针的指针 指向的对象pNode还是指针
{
node *tmp;
node *target;
int i=1;
while(i <= item)
{
if(* pNode == NULL)
{
*pNode = (node *)malloc(sizeof(LinkList));
if(!(* pNode))
{
exit(0);//退出
}
(*pNode)->data = i;
(*pNode)->next = *pNode ;
i++;
}
else
{
target = *pNode;
while(target->next != *pNode)
{
target = target->next ;
}
tmp = (node*)malloc(sizeof(LinkList ));
if(! tmp)
{
exit(0);
}
tmp->data = i;
i++;
tmp->next = *pNode ;
target->next = tmp;
}
}
}
//遍历链表
void Traversal(node *pNode)
{
node *tmp;
tmp = pNode;
printf("\n\t\t*****************************链表元素*********************************\n\n");
do
{
printf("\t%d",tmp->data );
tmp = tmp->next ;
}while(tmp->next != pNode);
printf("\t%d",tmp->data );
puts("");
}
//删除结点(杀人)
void DeleteNode(node **pNode,int x,int y)
{
int people = 1;
int Key[80];
printf("请依次输入每人的密码(使用空格隔开):\n\n");
for(int i=1;i<=y;++i)
{
scanf("%d",&Key[i]);
}
printf("出列顺序:\n\n");
node *target;
target = *pNode ;
while(people <= y)
{
node *tmp;
if(people != 1)
{
target = target->next ;
}
if(x != 1)
{
for(int i=1;i<x-1;++i)
{
target = target->next ;
}
tmp = target->next ;
printf("%d\t",tmp->data );//打印删除结点标号
x = Key[tmp->data ];
target->next = tmp ->next ;
free(tmp);
}
else
{
printf("%d\t",target->data );
}
people++;
}
}
int main()
{
printf("Designer by MaLong\n");
printf("\n\t\t**********************************************************************\n");
printf("\t\t* *\n");
printf("\t\t* *\n");
printf("\t\t********************欢迎来到约瑟夫杀人游戏****************************\n");
printf("\t\t* *\n");
printf("\t\t* *\n");
printf("\t\t**********************************************************************\n\n\n\n");
int x,y;
printf("请输入参与游戏的人数:\n");
scanf("%d",&y);
printf("请输入初始密码:\n");
scanf("%d",&x);
node *head = NULL;
Initialise (&head,y);
Traversal (head);
DeleteNode (&head,x,y);
return 0;
}
Operation result:
I hope to help you!
Please advise us on the shortcomings!