topic:
Analysis: A very simple greedy, I hope I can calmly analyze in the examination room.
From left to right, when the first pair of sums exceeds x, the one on the right is obviously deleted.
A pit, the minimum is 0.
Code:
#include<bits/stdc++.h>
using namespace std;
int m,x;
int A[100005];
int main()
{
cin>>m>>x;
for(int i=0;i<m;i++) cin>>A[i];
long long ans=0;
for(int i=0;i<m-1;i++)
{
if(A[i]+A[i+1]<=x) continue;
ans+=A[i]+A[i+1]-x;
int c=A[i]+A[i+1]-x;
A[i+1]=A[i+1]-c;
A[i+1]=max(A[i+1],0);
}
cout<<ans;
}