topic
For the two input integers, output the sum-difference quotient as required.
Input format:
Enter two non-negative integers a and b not exceeding 100 in a line, separated by a space in the middle, and ensure that b is not 0.
Output format:
A total of four lines, the format is:
[a] + [b] = [a+b]
[a] - [b] = [a-b]
[a] * [b] = [a*b]
[a] / [b] = [a/b]
Among them, the content with square brackets (such as [a], [b], [a + b], etc.) represents the corresponding integer or the value of the operation result, and the actual value should be replaced when output.
And: if a is divisible by b, then a / b should be output in integer format, otherwise a / b is output in a format with two decimal places.
Tip: Pay attention to the spaces in the expression.
Sample input:
6 3
Sample output:
6 + 3 = 9
6 - 3 = 3
6 * 3 = 18
6 / 3 = 2
Code
#include<stdio.h>
int main(){
int a,b,sum,minus,multiply,quotient,point;
scanf("%d %d",&a,&b);
if(a<=100 && a>=0 && b>0 && b<=100){
sum=a+b;
printf("%d + %d = %d\n",a,b,sum);
minus=a-b;
printf("%d - %d = %d\n",a,b,minus);
multiply=a*b;
printf("%d * %d = %d\n",a,b,multiply);
quotient=a*100/b;
point=quotient%100;
quotient/=100;
if(point==0){
printf("%d / %d = %d\n",a,b,quotient);
}else{
printf("%d / %d = %d.%d\n",a,b,quotient,point);
}
}
return 0;
}