;用移位指令实现al乘10(不带进位)
;思路:乘法本质其实是加法,先利用二进制的位移指令进行一次乘8再加两次自己。
assume cs:code
code segment
start: mov bl,al
mov cl,3
shl al,cl ;左移三位,相当于*8
add al,bl ;已经乘过8了,再加一次自己相当于乘9
add al,bl ;再加一次自己就相当于乘10
mov ax, 4c00H
int 21H
code ends
end start
Use shift instructions to achieve al multiplied by 10 (without carry)
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Origin blog.csdn.net/qq_43071318/article/details/105170067
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