assume cs:code
data segment
dw 1,2,3,4,5,6,7,8
dd 0,0,0,0,0,0,0,0
data ends
code segment
start: mov ax, data
mov ds, ax
mov si, 0 ;ds:si指向第一组word单元
mov di, 16 ;ds:di指向第二组dword单元
mov cx, 8
s:mov bx, [si]
call cube
mov [di], ax
mov [di].2, dx ;若发生进位,高位数据在dx中,把dx中的数据给ds:[di+2]
add si, 2 ;ds:si指向下一组word单元
add di, 4 ;ds:di指向下一个dword单元
loop s
mov ax, 4C00H
int 21H
cube:mov ax, bx
mul bx
mul bx
ret
code ends
end start
Use call and ret instructions to calculate the cube of data
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Origin blog.csdn.net/qq_43071318/article/details/105426114
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