1: multiple choice
The following () method is mainly used to represent floating-point representation in order code.
A: original code
B: Complement
C: Anti-code
D: frameshift
2: multiple choice
In the following statements about the relationship between complement and shift code, the error is ().
A: same number of bits and the complement represent frameshift table has the same number range
B: complement zero shift and refer to the same
C: the same number of complement and shift said same part of its value, but opposite signs
D: Order generally represented by the floating-point shift, complement representation and fixed-point integer
3: multiple choice
Two kinds of floating-point format is assumed that the number of bits is 32, but the order 1 code format of long and short mantissa and exponent format 2 is short, the mantissa length, all other provisions are the same. The accuracy and range of the number thereof may be expressed as ().
A: range and precision number may represent both are the same
B: a small number format may represent, but high precision
C: 2 small number may represent the format, but the high precision
D: number may represent a wide range of formats 1, precision and high
4: Multiple choice
Assuming IEEE754 single precision floating point format a number 45100000H, the value of this number is ().
A： +1.125*210
B： +1.125*211
C： +0.125*210
D： +0.125*211
5: multiple choice
In computer systems, the Western character encoding commonly used ().
A: BCD code
B: ASCII code
C: Gray code
D: CRC 码
6: multiple choice
In fixed point subtraction operator, either double or single sign bit symbol bits, there must be () circuit, which is generally implemented with exclusive-OR gate.
A: decoding
B: encoding
C: Overflow Analyzing
D: shift circuit
7: multiple choice
The following description of the ALU, the error is ().
A: ALU may be used to implement arithmetic and logic
B: two operands of the ALU must be from the general register
C: ALU available lookahead adder rapid manner
D: ALU operation type is determined by the instruction decoder of the execution result
8: multiple choice
Given the following character encoding contains the parity bit, but no data error occurs, then the use of odd character encoding is ().
A： 11010011
B： 01100110
C： 10110001
D： 10010101
9：单选题
某计算机字长为8位，其CPU中有一个8位加法器。已知无符号数x=69，y=38，现要在该加法器中完成x+y的运算，则该加法器的两个输入端信息和输入的低位进位信息分别为（ ）。
A： 0100 0101、0010 0110、0
B： 0100 0101、0010 0110、1
C： 0100 0101、1101 1010、0
D： 0100 0101、1101 1010、1
10：单选题
某8位计算机中，假定x和y是两个带符号整数变量，用补码表示，x=63，y=–31，则x–y的机器数及其相应的溢出标志OF分别是（ ）。