python algorithm - diamond print, peer triangle, lightning

1, diamond print

# - * - Coding: UTF- . 8 - * - 
# Version:. To python3 . 7 

'' '
    @ File   : print_graphics 
   @ author: zhangyangyang 
   @ Create: 2020 / . 3 / 22 is 
   @ the remark: ' 
''
 
# print diamond 
# version1: Derivation the number of spaces and ' * ' relationship between the number of spaces + "*" = n (length) 

n- = . 7 
E = n- // 2 
for I in Range (-e, + E . 1 ): defines the number of spaces #: [- . 3 , . 3 ]
     #if I <0: 
    # I = -I 
    #Print ( ' {} {} ' .format ( '  ' * I, (n-- 2 * I) * ' * ' )) 
    Print ( ' {} {} ' .format ( '  ' * ABS (I), (n-- 2 * ABS (I)) * ' * ' )) #abs (): absolute value 

execution results: 
   * 
  *** 
 ***** 
******* 
 ***** 
  ** * 
   *

# Version2: print centering 

n- =. 7 
E = n-2 //
 for I in Range (-e, + E. 1 ):
     Print ( " {:}} ^ { " .format ( ' * ' * (n-- 2 * ABS (i)), n)) 

The results:
    *    
  ***   
 ***** 
******* 
 ***** 
  ***   
   *   

 

2, printing of a triangle

# Vsrsion1 

n- =. 7 
E = n-2 //
 for I in Range (-e, + E. 1 ):
     # Print ( '' * (E - ABS (I)) + '{}'. The format ( '*' * (2 * ABS (I) +. 1))) 
    Print ( ' : {}} ^ { ' .format ( ' * ' * (2 * ABS (I) +. 1 ), n-)) 

The results:
 **** *** 
 ***** 
  *** 
   * 
  *** 
 ***** 
*******

# Version2 

n- =. 7 
E = n-2 //
 for I in Range (-e, N- E):
     Print ( ' {} {} ' .format ( '  ' * (E - ABS (I)), ' * ' * (2 * ABS (I) +. 1 ))) 

The results:
 ******* 
 ***** 
  *** 
   * 
  *** 
 ***** 
*******

 

3, Lightning Print

# Print Lightning 

n- =. 7 
E = n-2 // 
X = n-- E
 for I in Range (- E, X):
     IF I < 0:
         Print ( '  ' * -i + (X + I) * ' * ' )
     elif I> 0:
         Print ( '  ' * E + (X - I) * ' * ' )
     the else :
         Print ( ' * ' * n-) 

The results:
    * 
  ** 
 ***
*******
   ***
   **
   *