C language: print a solid diamond

Print a solid diamond

mission details

Input n and output the following pattern:

the input n in the above example is 4.
Requirements: use for loop to achieve

AC code

#include <stdio.h>
int main()
{
    
    
    int i, j, k, n; 
    scanf("%d", &n);
    //输出上半菱形 
	for(i = 1;i <= n;i++)
	{
    
    
    	for(k = 1;k <= n-i;k++)
    	printf(" ");
		for(j = 1;j < 2*i;j++)
    	printf("*");
		printf("\n");
	}
	//输出下半菱形 
	for(i = n-1;i >= 1;i--)
	{
    
    //i=3,2,1 
    	for(k = 1;k <= n-i;k++)
    	printf(" ");
		for(j = 1;j < 2*i;j++)
    	printf("*");
		printf("\n");
	}
    return 0;
}