1. Analyzing leap year
Import . Classes in java.util * ; public class One { public static void main (String [] args) { Scanner INPUT = new new Scanner (the System.in); System.out.println ( "Please enter a year:" ); Long year = input.nextLong (); IF (! year. 4 == 0 && year% 100% 400% year || = 0 == 0 ) { System.out.println (year + "is a leap year!" ); } the else { System.out.println (year + "is not a leap year" ); } } }
2. Enter a 4-digit card number, if one hundred number is a multiple of three, then the output is fortunate members, otherwise it is not output.
Import . Classes in java.util * ; public class One { public static void main (String [] args) { Scanner INPUT = new new Scanner (the System.in); System.out.println ( "Please enter the card number:" ); Long hykh = input.nextLong (); IF (hykh> && hykh 999 <9999 ) { IF (hykh 1000% / 100%. 3 == 0 ) { System.out.println ( "Ning oct transport member" ); } the else { the System.out .println ( "eight is your lucky member" ); } } The else { System.out.println ( "Please enter the card number 4" ); } } }
3. The value of the function is known, the value of the input x, output y of the corresponding.
X. 3 + (x> 0)
y = 0 (x = 0)
X2 -1 (x <0)
import java.util.*; public class One { public static void main(String[] args) { Scanner input = new Scanner(System.in); System.out.println("x:"); int x = input.nextInt(); if (x>0) { System.out.println("y="+(x+3)); }else if (x<0) { System.out.println("y="+(x*2-1)); }else { System.out.println("y=0"); } } }
4. Enter Number determined whether the three triangles can be constructed
import java.util.*; public class One { public static void main(String[] args) { Scanner input = new Scanner(System.in); System.out.println("输入三位数"); int x = input.nextInt(); int y = input.nextInt(); int z = input.nextInt(); if (x+y>z&&x+z>y&&y+z>x) { System.out.println("可以构成三角形"); }else { System.out.println("不!"); }